Model 2 Simplification based on square & square root Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC CPO S.I.2003]

Simplify $√{[(12.1)^2 - (8.1)^2] + [(0.25)^2 + (0.25)(19.95)]}$

a) 2

b) 3

c) 1

d) 4

Answer: (d)

$√{{20.2 × 4}/{0.25 × 20.2}} = √{4/{0.25}}$

= $√{400/25} = √{16}$ = 4

Question : 22

Simplification of ${(3.4567)^2 - (3.4533)^2}/{0.0034}$ yields the result :

a) 7

b) 6.81

c) 6.91

d) 7.1

Answer: (c)

? = ${(3.4567 + 3.4533)(3.4567 - 3.4533)}/{0.0034}$

= ${6.9100 × 0.0034}/{0.0034}$ = 6.91

Using Rule 8,

${(3.4567 + 3.4533)(3.4567 - 3.4533)}/{0.0034}$

= ${{3.4567}^2 - {3.4533}^2}/{(3.4567 - 3.4533)}$

= 3.4567 + 3.4533 = 6.91

Question : 23 [SSC CGL Tier-I 2010]

$√{{0.009 × 0.036 × 0.016 × 0.08}/{0.002 × 0.0008 × 0.0002}}$ is equal to

a) 36

b) 38

c) 34

d) 39

Answer: (a)

Expression

= $√{{0.009 × 0.036 × 0.016 × 0.08}/{0.002 × 0.0008 × 0.0002}}$

= $√{{9 × 36 × 16 × 8}/{2 × 8 × 2}}$

= 3 × 2 × 3 × 2 = 36

Question : 24 [SSC CGL Prelim 2000]

The square root of $({272}^2 - {128}^2)$ is :

a) 200

b) 240

c) 256

d) 144

Answer: (b)

? = $√{({272}^2 - {128}^2)}$

= $√{(272 + 128)(272 + 128)}$

= $√{400 × 144}$ = 20 × 12 = 240

Question : 25

The value of ${(0.03)^2 - (0.01)^2}/{0.03 - 0.01}$ is:

a) 0.004

b) 0.4

c) 0.02

d) 0.04

Answer: (d)

${(0.03)^2 - (0.01)^2}/{0.03 - 0.01}$

[Using ${a^2 - b^2}$ = (a + b)(a - b)]

= ${(0.03 + 0.01)(0.03 - 0.01)}/{0.03 - 0.01}$

= 0.03 + 0.01 = 0.04

Using Rule 8,

${(0.03)^2 - (0.01)^2}/{0.03 - 0.01}$

= (0.03 + 0.01 = 0.04

IMPORTANT quantitative aptitude EXERCISES

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